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백준 17129번 윌리암슨수액빨이딱따구리가 정보섬에 올라온 이유 C++ 본문

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백준 17129번 윌리암슨수액빨이딱따구리가 정보섬에 올라온 이유 C++

영춘권의달인 2022. 10. 23. 11:16

https://www.acmicpc.net/problem/17129

 

17129번: 윌리암슨수액빨이딱따구리가 정보섬에 올라온 이유

첫째 줄에 정보섬 2층의 크기 n과 m이 주어진다. (1 ≤ n,m ≤ 3000, 4 ≤ n×m ≤ 9×106) 이후 n행 m열에 걸쳐 0, 1, 2, 3, 4, 5로만 구성된 Ai,j가 주어진다. Ai,j와 Ai,j+1사이에 공백은 주어지지 않는다. 2,

www.acmicpc.net

 

bfs

 

#include <iostream>
#include <string>
#include <vector>
#include <math.h>
#include <algorithm>
#include <utility>
#include <stack>
#include <queue>
#include <math.h>
#include <set>
#include <map>
#include <list>
#include <unordered_map>
#include <unordered_set>
#include <iomanip>
#include <limits.h>

using namespace std;
using int64 = long long;

int dRow[4] = { -1,0,1,0 };
int dCol[4] = { 0,1,0,-1 };

vector<vector<int>> board;
vector<vector<bool>> found;

int n, m;

struct Info {
    int row;
    int col;
    int moveCnt;
};

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    
    cin >> n >> m;

    board = vector<vector<int>>(n, vector<int>(m));
    found = vector<vector<bool>>(n, vector<bool>(m, false));

    queue<Info> q;

    for (int i = 0; i < n; i++) {
        string str;
        cin >> str;
        for (int j = 0; j < m; j++) {
            board[i][j] = str[j] - '0';
            if (board[i][j] == 2) {
                q.push({ i,j,0 });
                found[i][j] = true;
            }
        }
    }

    int ans = -1;

    while (!q.empty()) {
        auto curr = q.front();
        q.pop();
        if (board[curr.row][curr.col] >= 3 && board[curr.row][curr.col] <= 5) {
            ans = curr.moveCnt;
            break;
        }
        for (int i = 0; i < 4; i++) {
            int nextRow = curr.row + dRow[i];
            int nextCol = curr.col + dCol[i];
            if (nextRow < 0 || nextRow >= n) continue;
            if (nextCol < 0 || nextCol >= m) continue;
            if (board[nextRow][nextCol] == 1) continue;
            if (found[nextRow][nextCol]) continue;
            found[nextRow][nextCol] = true;
            q.push({ nextRow,nextCol,curr.moveCnt + 1 });
        }
    }
    if (ans == -1) cout << "NIE";
    else cout << "TAK\n" << ans;
}