알고리즘
백준 6593번 상범 빌딩 C++
영춘권의달인
2022. 3. 16. 12:19
bfs인데, 상하 도 있기 때문에 보통의 2차원 배열이 아닌 3차원 배열을 이용해서 문제를 해결하였다.
#include <iostream>
#include <string>
#include <vector>
#include <math.h>
#include <algorithm>
#include <utility>
#include <stack>
#include <queue>
#include <math.h>
#include <set>
#include <map>
#include <unordered_map>
#include <unordered_set>
#include <iomanip>
using namespace std;
using ll = long long;
int dHeight[6] = { 1,-1, 0, 0, 0, 0 };
int dRow[6] = { 0, 0,-1, 0, 1, 0 };
int dCol[6] = { 0, 0, 0, 1, 0,-1 };
struct Info {
int h;
int r;
int c;
int cnt;
};
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int l, r, c;
while (true) {
cin >> l >> r >> c;
if (l == 0 && r == 0 && c == 0) break;
vector<vector<vector<char>>> board(l, vector<vector<char>>(r, vector<char>(c)));
vector<vector<vector<bool>>> found(l, vector<vector<bool>>(r, vector<bool>(c, false)));
Info start, end;
for (int i = 0; i < l; i++) {
for (int j = 0; j < r; j++) {
string str;
cin >> str;
for (int k = 0; k < c; k++) {
board[i][j][k] = str[k];
if (str[k] == 'S') {
start = { i,j,k,0 };
found[i][j][k] = true;
}
if (str[k] == 'E') end = { i,j,k,0 };
}
}
}
queue<Info> q;
q.push(start);
int ans = -1;
while (!q.empty()) {
auto curr = q.front();
if (curr.h == end.h && curr.r == end.r && curr.c == end.c) {
ans = curr.cnt;
break;
}
q.pop();
for (int i = 0; i < 6; i++) {
int nextH = curr.h + dHeight[i];
int nextRow = curr.r + dRow[i];
int nextCol = curr.c + dCol[i];
if (nextH < 0 || nextH >= l) continue;
if (nextRow < 0 || nextRow >= r) continue;
if (nextCol < 0 || nextCol >= c) continue;
if (board[nextH][nextRow][nextCol] == '#') continue;
if (found[nextH][nextRow][nextCol]) continue;
found[nextH][nextRow][nextCol] = true;
q.push({ nextH,nextRow,nextCol,curr.cnt + 1 });
}
}
if (ans == -1) {
cout << "Trapped!" << "\n";
}
else {
cout << "Escaped in " << ans << " minute(s)." << "\n";
}
}
};